Optimal. Leaf size=178 \[ \frac{b n \text{PolyLog}(2,-e x)}{3 e^3}-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{\log (e x+1) \left (a+b \log \left (c x^n\right )\right )}{3 e^3}+\frac{1}{3} x^3 \log (e x+1) \left (a+b \log \left (c x^n\right )\right )+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )+\frac{4 b n x}{9 e^2}-\frac{b n \log (e x+1)}{9 e^3}-\frac{5 b n x^2}{36 e}-\frac{1}{9} b n x^3 \log (e x+1)+\frac{2}{27} b n x^3 \]
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Rubi [A] time = 0.104293, antiderivative size = 178, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {2395, 43, 2376, 2391} \[ \frac{b n \text{PolyLog}(2,-e x)}{3 e^3}-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{\log (e x+1) \left (a+b \log \left (c x^n\right )\right )}{3 e^3}+\frac{1}{3} x^3 \log (e x+1) \left (a+b \log \left (c x^n\right )\right )+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )+\frac{4 b n x}{9 e^2}-\frac{b n \log (e x+1)}{9 e^3}-\frac{5 b n x^2}{36 e}-\frac{1}{9} b n x^3 \log (e x+1)+\frac{2}{27} b n x^3 \]
Antiderivative was successfully verified.
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Rule 2395
Rule 43
Rule 2376
Rule 2391
Rubi steps
\begin{align*} \int x^2 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x) \, dx &=-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (a+b \log \left (c x^n\right )\right ) \log (1+e x)}{3 e^3}+\frac{1}{3} x^3 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x)-(b n) \int \left (-\frac{1}{3 e^2}+\frac{x}{6 e}-\frac{x^2}{9}+\frac{\log (1+e x)}{3 e^3 x}+\frac{1}{3} x^2 \log (1+e x)\right ) \, dx\\ &=\frac{b n x}{3 e^2}-\frac{b n x^2}{12 e}+\frac{1}{27} b n x^3-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )+\frac{\left (a+b \log \left (c x^n\right )\right ) \log (1+e x)}{3 e^3}+\frac{1}{3} x^3 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x)-\frac{1}{3} (b n) \int x^2 \log (1+e x) \, dx-\frac{(b n) \int \frac{\log (1+e x)}{x} \, dx}{3 e^3}\\ &=\frac{b n x}{3 e^2}-\frac{b n x^2}{12 e}+\frac{1}{27} b n x^3-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )-\frac{1}{9} b n x^3 \log (1+e x)+\frac{\left (a+b \log \left (c x^n\right )\right ) \log (1+e x)}{3 e^3}+\frac{1}{3} x^3 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x)+\frac{b n \text{Li}_2(-e x)}{3 e^3}+\frac{1}{9} (b e n) \int \frac{x^3}{1+e x} \, dx\\ &=\frac{b n x}{3 e^2}-\frac{b n x^2}{12 e}+\frac{1}{27} b n x^3-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )-\frac{1}{9} b n x^3 \log (1+e x)+\frac{\left (a+b \log \left (c x^n\right )\right ) \log (1+e x)}{3 e^3}+\frac{1}{3} x^3 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x)+\frac{b n \text{Li}_2(-e x)}{3 e^3}+\frac{1}{9} (b e n) \int \left (\frac{1}{e^3}-\frac{x}{e^2}+\frac{x^2}{e}-\frac{1}{e^3 (1+e x)}\right ) \, dx\\ &=\frac{4 b n x}{9 e^2}-\frac{5 b n x^2}{36 e}+\frac{2}{27} b n x^3-\frac{x \left (a+b \log \left (c x^n\right )\right )}{3 e^2}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{6 e}-\frac{1}{9} x^3 \left (a+b \log \left (c x^n\right )\right )-\frac{b n \log (1+e x)}{9 e^3}-\frac{1}{9} b n x^3 \log (1+e x)+\frac{\left (a+b \log \left (c x^n\right )\right ) \log (1+e x)}{3 e^3}+\frac{1}{3} x^3 \left (a+b \log \left (c x^n\right )\right ) \log (1+e x)+\frac{b n \text{Li}_2(-e x)}{3 e^3}\\ \end{align*}
Mathematica [A] time = 0.0717883, size = 161, normalized size = 0.9 \[ \frac{36 b n \text{PolyLog}(2,-e x)-12 a e^3 x^3+18 a e^2 x^2+36 a e^3 x^3 \log (e x+1)-36 a e x+36 a \log (e x+1)+6 b \left (e x \left (-2 e^2 x^2+3 e x-6\right )+6 \left (e^3 x^3+1\right ) \log (e x+1)\right ) \log \left (c x^n\right )+8 b e^3 n x^3-15 b e^2 n x^2-12 b e^3 n x^3 \log (e x+1)+48 b e n x-12 b n \log (e x+1)}{108 e^3} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.076, size = 870, normalized size = 4.9 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.3672, size = 297, normalized size = 1.67 \begin{align*} \frac{{\left (\log \left (e x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (-e x\right )\right )} b n}{3 \, e^{3}} - \frac{{\left (b{\left (n - 3 \, \log \left (c\right )\right )} - 3 \, a\right )} \log \left (e x + 1\right )}{9 \, e^{3}} - \frac{4 \,{\left (3 \, a e^{3} -{\left (2 \, e^{3} n - 3 \, e^{3} \log \left (c\right )\right )} b\right )} x^{3} - 3 \,{\left (6 \, a e^{2} -{\left (5 \, e^{2} n - 6 \, e^{2} \log \left (c\right )\right )} b\right )} x^{2} - 12 \,{\left ({\left (4 \, e n - 3 \, e \log \left (c\right )\right )} b - 3 \, a e\right )} x - 12 \,{\left ({\left (3 \, a e^{3} -{\left (e^{3} n - 3 \, e^{3} \log \left (c\right )\right )} b\right )} x^{3} - 3 \, b n \log \left (x\right )\right )} \log \left (e x + 1\right ) + 6 \,{\left (2 \, b e^{3} x^{3} - 3 \, b e^{2} x^{2} + 6 \, b e x - 6 \,{\left (b e^{3} x^{3} + b\right )} \log \left (e x + 1\right )\right )} \log \left (x^{n}\right )}{108 \, e^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (b x^{2} \log \left (c x^{n}\right ) \log \left (e x + 1\right ) + a x^{2} \log \left (e x + 1\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \log \left (c x^{n}\right ) + a\right )} x^{2} \log \left (e x + 1\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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